In this article I will explain with an example, how to display DateTime in dd/MM/yyyy format using DataBinder.Eval function in ASP.Net using C# and VB.Net.
The DataBinder.Eval function is used to display data from Database in GridView, Repeater, DataList, FormView, etc. in ASP.Net.
 
 
HTML Markup
The HTML Markup consists of an ASP.Net Repeater control rendered as an HTML Table with three columns.
The DateTime field value is converted to dd/MM/yyyy by passing an additional parameter i.e. {0:dd/MM/yyyy} in order to format and display the DateTime field value in dd/MM/yyyy format.
<asp:Repeater ID="Repeater1" runat="server">
    <HeaderTemplate>
        <table cellspacing="0" rules="all" border="1">
            <tr>
                <th scope="col" style="width: 30px">Id</th>
                <th scope="col" style="width: 150px">Name</th>
                <th scope="col" style="width: 150px">Birth Date</th>
            </tr>
    </HeaderTemplate>
    <ItemTemplate>
        <tr>
            <td><%# Eval("Id")%></td>
            <td><%# Eval("Name")%></td>
            <td><%# Eval("BirthDate", "{0: dd/MM/yyyy}")%></td>
        </tr>
    </ItemTemplate>
    <FooterTemplate>
        </table>
    </FooterTemplate>
</asp:Repeater>
 
 
Namespaces
You will need to import the following namespace.
C#
using System.Data;
 
VB.Net
Imports System.Data
 
 
Populating the Repeater control
Inside the Page Load event, the Repeater control is populated with a DataTable containing some dummy records.
C#
protected void Page_Load(object sender, EventArgs e)
{
    if (!this.IsPostBack)
    {
        DataTable dt = new DataTable();
        dt.Columns.AddRange(new DataColumn[3] { new DataColumn("Id", typeof(int)),
                        new DataColumn("Name", typeof(string)),
                        new DataColumn("BirthDate",typeof(DateTime)) });
        dt.Rows.Add(1, "John Hammond", new DateTime(1975, 12, 1));
        dt.Rows.Add(2, "Mudassar Khan", new DateTime(1985, 2, 25));
        dt.Rows.Add(3, "Suzanne Mathews", new DateTime(1992, 3, 23));
        dt.Rows.Add(4, "Robert Schidner", new DateTime(1982, 1, 15));
        Repeater1.DataSource = dt;
        Repeater1.DataBind();
    }
}
 
VB.Net
Protected Sub Page_Load(ByVal sender As Object, ByVal e As EventArgs) Handles Me.Load
    If Not Me.IsPostBack Then
        Dim dt As DataTable = New DataTable()
        dt.Columns.AddRange(New DataColumn(2) {New DataColumn("Id", GetType(Integer)), New DataColumn("Name", GetType(String)), New DataColumn("BirthDate", GetType(DateTime))})
        dt.Rows.Add(1, "John Hammond", New DateTime(1975, 12, 1))
        dt.Rows.Add(2, "Mudassar Khan", New DateTime(1985, 2, 25))
        dt.Rows.Add(3, "Suzanne Mathews", New DateTime(1992, 3, 23))
        dt.Rows.Add(4, "Robert Schidner", New DateTime(1982, 1, 15))
        Repeater1.DataSource = dt
        Repeater1.DataBind()
    End If
End Sub
 
 
Screenshot
Display DateTime in dd/MM/yyyy format using DataBinder.Eval in ASP.Net
 
 
Demo
View Demo
 
 
Downloads
Download Code