In this article I will explain with an example, how to upload and save (insert) multiple files to SQL Server database in ASP.Net using C# and VB.Net.
ASP.Net 4.5 has a new property AllowMultiple for FileUpload control, which allows user to select and upload multiple files. This property will work only in browsers that support HTML5.
Database
This article makes use of a table named tblFiles whose schema is defined as follows.
Note: You can download the database table SQL by clicking the download link below.
Download SQL file
HTML Markup
The HTML Markup consists of a FileUpload control, a Button and a GridView control. For the FileUpload control AllowMultiple property is to true.
<asp:FileUpload ID="FileUpload1" runat="server" AllowMultiple="true" />
<asp:Button ID="btnUpload" runat="server" Text="Upload" OnClick="Upload" />
<hr />
<asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="false">
<Columns>
<asp:BoundField DataField="Name" HeaderText="File Name" />
</Columns>
</asp:GridView>
Namespaces
You will need to import the following namespaces.
C#
using System.IO;
using System.Data;
using System.Data.SqlClient;
using System.Configuration;
VB.Net
Imports System.IO
Imports System.Data
Imports System.Data.SqlClient
Imports System.Configuration
Uploading and inserting multiple files to database in ASP.Net
The below event handler gets executed when the Upload Button is clicked, it executes a loop over the FileUpload’s PostedFiles property and saves each file as Binary data in the SQL Server Database.
The name of the file, the content type (MIME type) and the actual file as array of bytes are inserted into the database table.
Note: The Content type (MIME type) is very important while downloading the files as it notifies the browser about type of the File.
C#
protected void Upload(object sender, EventArgs e)
{
foreach (HttpPostedFile postedFile in FileUpload1.PostedFiles)
{
string filename = Path.GetFileName(postedFile.FileName);
string contentType = postedFile.ContentType;
using (Stream fs = postedFile.InputStream)
{
using (BinaryReader br = new BinaryReader(fs))
{
byte[] bytes = br.ReadBytes((Int32)fs.Length);
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (SqlConnection con = new SqlConnection(constr))
{
string query = "insert into tblFiles values (@Name, @ContentType, @Data)";
using (SqlCommand cmd = new SqlCommand(query))
{
cmd.Connection = con;
cmd.Parameters.AddWithValue("@Name", filename);
cmd.Parameters.AddWithValue("@ContentType", contentType);
cmd.Parameters.AddWithValue("@Data", bytes);
con.Open();
cmd.ExecuteNonQuery();
con.Close();
}
}
}
}
}
Response.Redirect(Request.Url.AbsoluteUri);
}
VB.Net
Protected Sub Upload(sender As Object, e As EventArgs)
For Each postedFile As HttpPostedFile In FileUpload1.PostedFiles
Dim filename As String = Path.GetFileName(postedFile.FileName)
Dim contentType As String = postedFile.ContentType
Using fs As Stream = postedFile.InputStream
Using br As New BinaryReader(fs)
Dim bytes As Byte() = br.ReadBytes(Convert.ToInt32(fs.Length))
Dim constr As String = ConfigurationManager.ConnectionStrings("constr").ConnectionString
Using con As New SqlConnection(constr)
Dim query As String = "insert into tblFiles values (@Name, @ContentType, @Data)"
Using cmd As New SqlCommand(query)
cmd.Connection = con
cmd.Parameters.AddWithValue("@Name", filename)
cmd.Parameters.AddWithValue("@ContentType", contentType)
cmd.Parameters.AddWithValue("@Data", bytes)
con.Open()
cmd.ExecuteNonQuery()
con.Close()
End Using
End Using
End Using
End Using
Next
Response.Redirect(Request.Url.AbsoluteUri)
End Sub
Displaying inserted files from Database in GridView
The GridView is populated with records from the tblFiles table in the Page Load event.
C#
protected void Page_Load(object sender, EventArgs e)
{
if (!IsPostBack)
{
this.BindGrid();
}
}
private void BindGrid()
{
string constr = ConfigurationManager.ConnectionStrings["constr"].ConnectionString;
using (SqlConnection con = new SqlConnection(constr))
{
using (SqlCommand cmd = new SqlCommand())
{
cmd.CommandText = "SELECT Id, Name FROM tblFiles";
cmd.Connection = con;
con.Open();
GridView1.DataSource = cmd.ExecuteReader();
GridView1.DataBind();
con.Close();
}
}
}
VB.Net
Protected Sub Page_Load(sender As Object, e As EventArgs) Handles Me.Load
If Not IsPostBack Then
Me.BindGrid()
End If
End Sub
Private Sub BindGrid()
Dim constr As String = ConfigurationManager.ConnectionStrings("constr").ConnectionString
Using con As New SqlConnection(constr)
Using cmd As New SqlCommand()
cmd.CommandText = "SELECT Id, Name FROM tblFiles"
cmd.Connection = con
con.Open()
GridView1.DataSource = cmd.ExecuteReader()
GridView1.DataBind()
con.Close()
End Using
End Using
End Sub
Screenshot
Downloads