[Solved] ASP.Net jQuery Ajax Error: Could not find file C:\\fakepath

Hi Jilsoft,

Use Generic Handler to upload the files using FormData and jQuery Ajax.

Refer below example.

HTML

<div>
    <input type="file" name="fuUpload" id="fuUpload" multiple="multiple" />
    <input name="txtName" type="text" id="txtName" />
    <asp:Button ID="btnSave" runat="server" Text="Save" value="Save" />
</div>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script type="text/javascript">
    $(function () {
        $('#btnSave').on("click", function () {
            var formData = new FormData();
            for (var i = 0; i < $("#fuUpload").prop("files").length; i++) {
                formData.append($("#fuUpload").prop("files")[i].name, $("#fuUpload").prop("files")[i]);
            }
            formData.append("Name", $('#txtName').val());
            $.ajax({
                type: 'POST',
                url: "Handler.ashx",
                data: formData,
                cache: false,
                contentType: false,
                processData: false,
                success: function (r) {
                    alert(r.d);
                },
                error: function (r) {
                    alert(r.responseText);
                }
            })
            return false;
        });
    });
</script>

Handler

C#

<%@ WebHandler Language="C#" Class="Handler" %>

using System;
using System.Web;
using System.Configuration;
using System.Data.SqlClient;
using System.IO;

public class Handler : IHttpHandler
{
    public void ProcessRequest(HttpContext context)
    {
        if (context.Request.Files.Count > 0)
        {
            string name = context.Request["Name"];
            foreach (string fName in context.Request.Files)
            {
                HttpPostedFile file = context.Request.Files[fName];
                file.SaveAs(HttpContext.Current.Server.MapPath("~/Files/" + Path.GetFileName(file.FileName)));
                SaveDetails(name, "~/Files/" + Path.GetFileName(file.FileName), Path.GetFileName(file.FileName));
            }
        }
    }

    private static void SaveDetails(string name, string filePath, string fileName)
    {
        string str = ConfigurationManager.ConnectionStrings["conn"].ConnectionString;
        using (SqlConnection con = new SqlConnection(str))
        {
            con.Open();
            using (SqlCommand cmd = new SqlCommand("Insert INTO Files (Name,FilePath,FileName) values (@Name,@FilePath,@FileName)", con))
            {
                cmd.Parameters.AddWithValue("@Name", name);
                cmd.Parameters.AddWithValue("@FilePath", filePath);
                cmd.Parameters.AddWithValue("@FileName", fileName);
                cmd.ExecuteNonQuery();
            }
            con.Close();
        }
    }

    public bool IsReusable
    {
        get
        {
            return false;
        }
    }
}

VB.Net

<%@ WebHandler Language="VB" Class="Handler" %>

Imports System
Imports System.Configuration
Imports System.Data.SqlClient
Imports System.IO

Public Class Handler : Implements IHttpHandler

    Public Sub ProcessRequest(ByVal context As HttpContext) Implements IHttpHandler.ProcessRequest
        If context.Request.Files.Count > 0 Then
            Dim name As String = context.Request("Name")
             For Each fName As String In context.Request.Files
                 Dim file As HttpPostedFile = context.Request.Files(fName)
                file.SaveAs(HttpContext.Current.Server.MapPath("~/Files/" & Path.GetFileName(file.FileName)))
                SaveDetails(name, "~/Files/" & Path.GetFileName(file.FileName), Path.GetFileName(file.FileName))
            Next
        End If
    End Sub

    Private Shared Sub SaveDetails(ByVal name As String, ByVal filePath As String, ByVal fileName As String)
        Dim str As String = ConfigurationManager.ConnectionStrings("conn").ConnectionString
        Using con As SqlConnection = New SqlConnection(str)
            con.Open()
            Using cmd As SqlCommand = New SqlCommand("Insert INTO Files (Name,FilePath,FileName) values (@Name,@FilePath,@FileName)", con)
                cmd.Parameters.AddWithValue("@Name", name)
                cmd.Parameters.AddWithValue("@FilePath", filePath)
                cmd.Parameters.AddWithValue("@FileName", fileName)
                cmd.ExecuteNonQuery()
            End Using
            con.Close()
        End Using
    End Sub

    Public ReadOnly Property IsReusable() As Boolean Implements IHttpHandler.IsReusable
        Get
            Return False
        End Get
    End Property

End Class