Show Hide Add Edit LinkButton for Authenticated user inside FormView using C# and VB.Net in ASP.Net

Hi micah,

Please refer below code and modify as per your requirement.

HTML

<form id="form1" runat="server">
<div>
    <asp:FormView ID="FormView1" runat="server" OnDataBound="FormView1_DataBound">
        <ItemTemplate>
            <table border="0" cellpadding="0" cellspacing="0">
                <tr>
                    <td>
                        ID:
                    </td>
                    <td>
                        <asp:ImageButton ID="UserImage" ImageUrl='<%# "Images/" + Eval("Name") %>' ToolTip='<%#Eval("Name")%>'
                            Width="80px" Height="50px" runat="server" />
                    </td>
                </tr>
                <tr>
                    <td>
                        Name:
                    </td>
                    <td>
                        <asp:Label ID="lblUserName" Text='<%# Eval("UserName") %>' runat="server" />
                    </td>
                </tr>
                <tr>
                    <td>
                        Email Id:
                    </td>
                    <td>
                        <%# Eval("Email") %>
                    </td>
                </tr>
                <tr>
                    <td>
                        <asp:LinkButton ID="btnAdd" Visible="false" runat="server">Add</asp:LinkButton>
                    </td>
                    <td>
                        <asp:LinkButton ID="btnEdit" Visible="false" runat="server">Edit</asp:LinkButton>
                    </td>
                </tr>
            </table>
        </ItemTemplate>
    </asp:FormView>
</div>
</form>

C#

private string constring = ConfigurationManager.ConnectionStrings["constring"].ToString();
protected void Page_Load(object sender, EventArgs e)
{
    if (!IsPostBack)
    {
        this.GetData();
    }
}

private void GetData()
{
    using (SqlConnection con = new SqlConnection(constring))
    {
        con.Open();
        using (SqlCommand cmd = new SqlCommand("SELECT * FROM [User] INNER Join Files On Files.UserName=[User].UserName WHERE [user].UserName=@UserName", con))
        {
            cmd.Parameters.AddWithValue("@UserName", Request.QueryString["UserName"].ToString());
            cmd.CommandType = CommandType.Text;
            SqlDataAdapter sda = new SqlDataAdapter(cmd);
            DataTable dt = new DataTable();
            sda.Fill(dt);
            FormView1.DataSource = dt;
            FormView1.DataBind();
        }
    }
}

protected void FormView1_DataBound(object sender, EventArgs e)
{
    if (FormView1.Row.RowType == DataControlRowType.DataRow)
    {
        string username = (FormView1.Row.FindControl("lblUserName") as Label).Text;
        if (username == Session["UserName"].ToString())
        {
            (FormView1.Row.FindControl("btnEdit") as LinkButton).Visible = true;
        }
        else
        {
            (FormView1.Row.FindControl("btnAdd") as LinkButton).Visible = true;
        }
    }
}

Vb.net

Private constring As String = ConfigurationManager.ConnectionStrings("constring").ToString()
Protected Sub Page_Load(sender As Object, e As EventArgs)
	If Not IsPostBack Then
		Me.GetData()
	End If
End Sub

Private Sub GetData()
	Using con As New SqlConnection(constring)
		con.Open()
		Using cmd As New SqlCommand("SELECT * FROM [User] INNER Join Files On Files.UserName=[User].UserName WHERE [user].UserName=@UserName", con)
			cmd.Parameters.AddWithValue("@UserName", Request.QueryString("UserName").ToString())
			cmd.CommandType = CommandType.Text
			Dim sda As New SqlDataAdapter(cmd)
			Dim dt As New DataTable()
			sda.Fill(dt)
			FormView1.DataSource = dt
			FormView1.DataBind()
		End Using
	End Using
End Sub

Protected Sub FormView1_DataBound(sender As Object, e As EventArgs)
	If FormView1.Row.RowType = DataControlRowType.DataRow Then
		Dim username As String = TryCast(FormView1.Row.FindControl("lblUserName"), Label).Text
		If username = Session("UserName").ToString() Then
			TryCast(FormView1.Row.FindControl("btnEdit"), LinkButton).Visible = True
		Else
			TryCast(FormView1.Row.FindControl("btnAdd"), LinkButton).Visible = True
		End If
	End If
End Sub

Screenshot