Argument of type is not assignable to parameter of type number in Angular

ramitaherwahdan1978 says:

token = localStorage.getItem("token");

The localStorage.getItem returns null. So use the nullish coalescing operator (??) to return the number 0 if localStorage returns null.

token = localStorage.getItem("token") ?? 0;

Reference: https://jasonwatmore.com/post/2022/11/10/angular-fix-for-argument-of-type-string-null-is-not-assignable-to-parameter-of-type-string

token = localStorage.getItem("token");
 
timeLeft = 120;
minutes = this.timeLeft / 60 % 60;
seconds = this.timeLeft %  60;
    
  interval = setInterval(() =>
  {
    if (this.token > 0)
    {
      const parseJwt = (this.token);      
      const decode = JSON.parse(atob(this.token.split('.')[1]));
      if (decode.exp * 1000 >= new Date().getTime())
      {
        if(this.seconds == 0)
        {
          this.minutes--;
          this.seconds = 59;
        }
        else if(this.seconds <= 59)
        {
          this.seconds--;
        }
        else if((this.minutes == 0) && (this.seconds == 0))
        {
            clearInterval(interval);
        }
      }
   }      
},1000)