Display all Employees In and Out Time of each Day in SQL Server

I figure out this approach.

create table #tempStatus (EmpId int, intTime datetime, sStatus int)        
insert into #tempStatus        
values(1, '2018-05-26 08:44', 1),        
    (1, '2018-05-26 08:44', 2),        
    (2, '2018-05-28 08:44', 1),        
    (2, '2018-05-28 12:44', 2),            
    (1, '2018-05-21 08:44', 1),        
    (1, '2018-05-21 10:44', 2),            
    (2, '2018-05-23 08:44', 1),        
    (2, '2018-05-23 08:44', 2),  
    (3, '2018-05-23 08:44', 1)  
      
select EmpId, MIN(intTime) as intTime, MAX(intTime) as OutTime into #tempA from (      
select EmpId, intTime, intTime as OutTime      
from #tempStatus where sStatus = 1      
)a       
group by EmpId, intTime      
      
update s      
set s.OutTime = t.outTime      
from #tempA s      
left join     
(    
select EmpId, MAX(outTime) as outTime from(       
select EmpId, intTime as outTime      
from #tempStatus where sStatus = 2      
)b       
group by empId,outTime) t     
on s.EmpId = t.EmpId and Convert(Varchar,s.OutTime,112) =  Convert(Varchar,t.outTime,112)      
      
select * from #tempA order by EmpId      
      
drop table #tempA      
DROP TABLE #tempStatus