How do i display a panel by clicking a button inside datalist

Hi Micah,

I have created sample. Please refer the below code. Here panel contains the name.

HTML

<div>
    <asp:DataList ID="GetAll" runat="server">
        <ItemTemplate>
            <table>
                <tr>
                    <td>
                        <asp:Label ID="Label1" Text='<%#DataBinder.Eval(Container.DataItem,"Id") %>' runat="server" />
                    </td>
                    <td>
                        <asp:Panel ID="Panel1" runat="server" Visible="false">
                            <asp:Label ID="Label2" Text='<%#DataBinder.Eval(Container.DataItem,"Name") %>' runat="server" />
                        </asp:Panel>
                    </td>
                    <td>
                        <asp:LinkButton ID="btnDisplayPanel" runat="server" OnClick="ShowPanel">Display Name</asp:LinkButton>
                    </td>
                </tr>
            </table>
        </ItemTemplate>
    </asp:DataList>
</div>

Code

protected void Page_Load(object sender, EventArgs e)
{
    if (!this.IsPostBack)
    {
        DataTable dt = new DataTable();
        dt.Columns.AddRange(new DataColumn[2] { new DataColumn("Id", typeof(int)), new DataColumn("Name") });
        dt.Rows.Add(1, "John Hammond");
        dt.Rows.Add(2, "Mudassar Khan");
        dt.Rows.Add(3, "Suzanne Mathews");
        dt.Rows.Add(4, "Robert Schidner");
        GetAll.DataSource = dt;
        GetAll.DataBind();
    }
}

protected void ShowPanel(object sender, EventArgs e)
{
    DataListItem item = (DataListItem)(sender as LinkButton).NamingContainer;
    Panel pnl = item.FindControl("Panel1") as Panel;
    if (((LinkButton)(sender)).Text.Trim() == "Display Name")
    {
        ((System.Web.UI.WebControls.LinkButton)(sender)).Text = "Hide Name";
    }
    else
    {
        ((System.Web.UI.WebControls.LinkButton)(sender)).Text = "Display Name";
    }
    if (pnl.Visible == false)
    {
        pnl.Visible = true;
    }
    else
    {
        pnl.Visible = false;
    }
}

Screenshot